What is expand log_{10}(2)(2x(x-16)) ?

The solution to expand log_{10}(2)(2x(x-16)) is 2log_{10}(2)x^2-32log_{10}(2)x

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expand log_{10}(2)(2x(x-16))

expand

lo g_{10} (2) (2 x (x - 16))

2 lo g_{10} (2) x^{2} - 32 lo g_{10} (2) x

Solution steps

lo g_{10} (2) (2 x (x - 16))

Remove parentheses:

(a) = a

= lo g_{10} (2) \cdot 2 x (x - 16)

= 2 lo g_{10} (2) x (x - 16)

Apply the distributive law:

a (b - c) = ab - a c

a = lo g_{10} (2) \cdot 2 x, b = x, c = 16

= lo g_{10} (2) \cdot 2 xx - lo g_{10} (2) \cdot 2 x \cdot 16

= 2 lo g_{10} (2) xx - 2 \cdot 16 lo g_{10} (2) x

Simplify

2 lo g_{10} (2) xx - 2 \cdot 16 lo g_{10} (2) x : 2 lo g_{10} (2) x^{2} - 32 lo g_{10} (2) x

= 2 lo g_{10} (2) x^{2} - 32 lo g_{10} (2) x

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What is expand log_{10}(2)(2x(x-16)) ?
The solution to expand log_{10}(2)(2x(x-16)) is 2log_{10}(2)x^2-32log_{10}(2)x