What is the d/(dy)((x)(x^2-2xy)) ?

The d/(dy)((x)(x^2-2xy)) is -2x^2

What is the first d/(dy)((x)(x^2-2xy)) ?

The first d/(dy)((x)(x^2-2xy)) is -2x^2

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\frac{d}{d y} ((x) (x^{2} - 2 x y))

- 2 x^{2}

Solution steps

\frac{d}{d y} ((x) (x^{2} - 2 x y))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x \frac{d}{d y} (x^{2} - 2 x y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= x (\frac{d}{d y} (x^{2}) - \frac{d}{d y} (2 x y))

\frac{d}{d y} (x^{2}) = 0

\frac{d}{d y} (2 x y) = 2 x

= x (0 - 2 x)

Simplify

x (0 - 2 x) : - 2 x^{2}

= - 2 x^{2}

(20 - π x)^{2}

9 a^{2 (10 a + 5 a^{2})}

\frac{( 2 s - 1 ) ^{2}}{( s + 3 ) ^{5}}

\frac{( x + 4 ) ^{5}}{x ^{5} + 4}

\frac{( x ^{2} - 6 )}{2 x}

What is the d/(dy)((x)(x^2-2xy)) ?
The d/(dy)((x)(x^2-2xy)) is -2x^2
What is the first d/(dy)((x)(x^2-2xy)) ?
The first d/(dy)((x)(x^2-2xy)) is -2x^2