What is expand e^{9x}(e^{2x}-e^x) ?

The solution to expand e^{9x}(e^{2x}-e^x) is e^{11x}-e^{10x}

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expand e^{9x}(e^{2x}-e^x)

expand

e^{9 x} (e^{2 x} - e^{x})

e^{11 x} - e^{10 x}

Solution steps

e^{9 x} (e^{2 x} - e^{x})

Apply the distributive law:

a (b - c) = ab - a c

a = e^{9 x}, b = e^{2 x}, c = e^{x}

= e^{9 x} e^{2 x} - e^{9 x} e^{x}

= e^{9 x} e^{2 x} - e^{x} e^{9 x}

Simplify

e^{9 x} e^{2 x} - e^{x} e^{9 x} : e^{11 x} - e^{10 x}

= e^{11 x} - e^{10 x}

\frac{x - 1}{( x + 5 ) ( x ^{2} + 3 )}

l (t^{2} + 2 e^{- 2 t})

\frac{x - 5}{x ( x - 1 ) ( x + 3 )}

- 2 (x^{2} = 3 x - 7) - 11

\frac{1}{s ( s - 1 ) ( s ^{2} - 4 )}

What is expand e^{9x}(e^{2x}-e^x) ?
The solution to expand e^{9x}(e^{2x}-e^x) is e^{11x}-e^{10x}