What is expand-(e^x(x-1)) ?

The solution to expand-(e^x(x-1)) is -e^xx+e^x

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expand-(e^x(x-1))

expand

- (e^{x} (x - 1))

- e^{x} x + e^{x}

Solution steps

- (e^{x} (x - 1))

Remove parentheses:

(a) = a

= - e^{x} (x - 1)

Apply the distributive law:

a (b - c) = ab - a c

a = - e^{x}, b = x, c = 1

= - e^{x} x - (- e^{x}) \cdot 1

Apply minus-plus rules

- (- a) = a

= - e^{x} x + 1 \cdot e^{x}

Multiply:

1 \cdot e^{x} = e^{x}

= - e^{x} x + e^{x}

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