What is expand (4x-1)(4x+1)' ?

The solution to expand (4x-1)(4x+1)' is 4x(4x+1)'-(4x+1)'

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expand (4x-1)(4x+1)'

expand

(4 x - 1) (4 x + 1)^{'}

4 x (4 x + 1)' - (4 x + 1)'

Solution steps

(4 x - 1) (4 x + 1)^{'}

Apply the distributive law:

a (b - c) = ab - a c

a = (4 x + 1)^{'}, b = 4 x, c = 1

= (4 x + 1)^{^{'}} 4 x - (4 x + 1)^{^{'}} 1

= 4 x (4 x + 1)^{^{'}} - 1 (4 x + 1)^{^{'}}

Multiply:

1 (4 x + 1)^{'} = (4 x + 1)^{'}

= 4 x (4 x + 1)^{^{'}} - (4 x + 1)^{^{'}}

\frac{375 ( π + 1 )}{π} - 375 - 2 π r^{2}

2 (x^{2} e^{- 2 x} + x e^{- 2 x})

\frac{( 2 b - 22 ) ^{2}}{12}

\frac{s ^{3}}{( s + w ) ^{2}}

8 \times (6 - 10.2)

What is expand (4x-1)(4x+1)' ?
The solution to expand (4x-1)(4x+1)' is 4x(4x+1)'-(4x+1)'