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Popular >

simplify e^{-ln(x^2+4)}

Solution

simplify

e^{- l n (x^{2} + 4)}

Solution

\frac{1}{x ^{2} + 4}

Solution steps

e^{- l n (x^{2} + 4)}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{l n (x^{2} + 4)}}

e^{l n (x^{2} + 4)} = x^{2} + 4

= \frac{1}{x ^{2} + 4}

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Frequently Asked Questions (FAQ)

What is e^{-ln(x^2+4)} ?
The solution to e^{-ln(x^2+4)} is 1/(x^2+4)