What is ((2x-6)/y)/(\frac{x-3){y+1}} ?

The solution to ((2x-6)/y)/(\frac{x-3){y+1}} is (2(y+1))/y

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simplify ((2x-6)/y)/(\frac{x-3){y+1}}

simplify

\frac{\frac{2 x - 6}{y}}{\frac{x - 3}{y + 1}}

\frac{2 ( y + 1 )}{y}

Solution steps

\frac{\frac{2 x - 6}{y}}{\frac{x - 3}{y + 1}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( 2 x - 6 ) ( y + 1 )}{y ( x - 3 )}

Cancel

\frac{( 2 x - 6 ) ( y + 1 )}{y ( x - 3 )} : \frac{2 ( y + 1 )}{y}

= \frac{2 ( y + 1 )}{y}

(0.008)^{- \frac{2}{3}}

x^{7} - 2 x^{5} - 1

\frac{t ^{2}}{2} + 4 t + 5 = 0

(- 2 + - 8) + (5 - - 50)

2 x^{2} + 5 x = 4

What is ((2x-6)/y)/(\frac{x-3){y+1}} ?
The solution to ((2x-6)/y)/(\frac{x-3){y+1}} is (2(y+1))/y