What is (3.7x10^{-13})(2.68x10^{-22}) ?

The solution to (3.7x10^{-13})(2.68x10^{-22}) is (9.916x^2)/(10^{35)}

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simplify (3.7x10^{-13})(2.68x10^{-22})

simplify

(3.7 x 1 0^{- 13}) (2.68 x 1 0^{- 22})

\frac{9.916 x ^{2}}{1 0 ^{35}}

Solution steps

(3.7 x \cdot 1 0^{- 13}) (2.68 x \cdot 1 0^{- 22})

Simplify

3.7 x \cdot 1 0^{- 13} : \frac{3.7 x}{1 0 ^{13}}

= \frac{3.7 x}{1 0 ^{13}} \cdot 2.68 x \cdot 1 0^{- 22}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 22} = \frac{1}{1 0 ^{22}}

= \frac{3.7 x}{1 0 ^{13}} \cdot 2.68 x \frac{1}{1 0 ^{22}}

Apply the fraction rule:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{3.7 x \cdot 2.68 x \cdot 1}{1 0 ^{13} \cdot 1 0 ^{22}}

Simplify

3.7 x \cdot 2.68 x \cdot 1 : 9.916 x^{2}

= \frac{9.916 x ^{2}}{1 0 ^{13} \cdot 1 0 ^{22}}

1 0^{13} \cdot 1 0^{22} = 1 0^{35}

= \frac{9.916 x ^{2}}{1 0 ^{35}}

(2 x^{3}) (3 x^{4})

5 x^{2} (x + y)^{2}

4 \cdot 0.1 \cdot 1 0^{- 3}

f (x) = tan^{2} (x) \cdot sec^{2} (x)

e^{- (l n (x) + \frac{1}{2})}

What is (3.7x10^{-13})(2.68x10^{-22}) ?
The solution to (3.7x10^{-13})(2.68x10^{-22}) is (9.916x^2)/(10^{35)}