What are the solutions to the equation 2x^2+34x+144=0 ?

The solutions to the equation 2x^2+34x+144=0 are x=-8,x=-9

Find the zeros of 2x^2+34x+144=0

The zeros of 2x^2+34x+144=0 are x=-8,x=-9

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2 x^{2} + 34 x + 144 = 0

x = - 8, x = - 9

Solution steps

2 x^{2} + 34 x + 144 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 34 \pm 3 4 ^{2} - 4 \cdot 2 \cdot 144}{2 \cdot 2}

3 4^{2} - 4 \cdot 2 \cdot 144 = 2

x_{1, 2} = \frac{- 34 \pm 2}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 34 + 2}{2 \cdot 2}, x_{2} = \frac{- 34 - 2}{2 \cdot 2}

x = \frac{- 34 + 2}{2 \cdot 2} : - 8

x = \frac{- 34 - 2}{2 \cdot 2} : - 9

The solutions to the quadratic equation are:

x = - 8, x = - 9

\frac{- 9}{2} x^{- \frac{11}{10}}

\frac{( c + 2 ) ( c - 1 )}{c + 2}

\frac{( x ^{2} + 1 )}{2} \geq 1

\frac{1 + 3 i}{1 + i}

x^{3} - 6 x^{2} - 5 x

What are the solutions to the equation 2x^2+34x+144=0 ?
The solutions to the equation 2x^2+34x+144=0 are x=-8,x=-9
Find the zeros of 2x^2+34x+144=0
The zeros of 2x^2+34x+144=0 are x=-8,x=-9