What are the solutions to the equation 3x^2-5x-4=0 ?

The solutions to the equation 3x^2-5x-4=0 are x=(5+sqrt(73))/6 ,x=(5-sqrt(73))/6

Find the zeros of 3x^2-5x-4=0

The zeros of 3x^2-5x-4=0 are x=(5+sqrt(73))/6 ,x=(5-sqrt(73))/6

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3 x^{2} - 5 x - 4 = 0

x = \frac{5 + 73}{6}, x = \frac{5 - 73}{6}

Decimal Notation

x = 2.25733 \dots, x = - 0.59066 \dots

Solution steps

3 x^{2} - 5 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 3 ( - 4 )}{2 \cdot 3}

(- 5)^{2} - 4 \cdot 3 (- 4) = 73

x_{1, 2} = \frac{- ( - 5 ) \pm 73}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 73}{2 \cdot 3}, x_{2} = \frac{- ( - 5 ) - 73}{2 \cdot 3}

x = \frac{- ( - 5 ) + 73}{2 \cdot 3} : \frac{5 + 73}{6}

x = \frac{- ( - 5 ) - 73}{2 \cdot 3} : \frac{5 - 73}{6}

The solutions to the quadratic equation are:

x = \frac{5 + 73}{6}, x = \frac{5 - 73}{6}

5^{- 2} = \frac{1}{25}

(x + 1) (2 x - 3) \geq (x + 1) (x - 3)

17 + \frac{- 18}{6}

(m + 3) + 0.7 \geq - 0.3 (- m + \frac{1}{4})

16 x^{2} - 100

What are the solutions to the equation 3x^2-5x-4=0 ?
The solutions to the equation 3x^2-5x-4=0 are x=(5+sqrt(73))/6 ,x=(5-sqrt(73))/6
Find the zeros of 3x^2-5x-4=0
The zeros of 3x^2-5x-4=0 are x=(5+sqrt(73))/6 ,x=(5-sqrt(73))/6