What are the solutions to the equation 7=b^2-6b ?

The solutions to the equation 7=b^2-6b are b=7,b=-1

Find the zeros of 7=b^2-6b

The zeros of 7=b^2-6b are b=7,b=-1

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7 = b^{2} - 6 b

b = 7, b = - 1

Solution steps

7 = b^{2} - 6 b

Switch sides

b^{2} - 6 b = 7

Move

7

to the left side

b^{2} - 6 b - 7 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 7) = 8

b_{1, 2} = \frac{- ( - 6 ) \pm 8}{2 \cdot 1}

Separate the solutions

b_{1} = \frac{- ( - 6 ) + 8}{2 \cdot 1}, b_{2} = \frac{- ( - 6 ) - 8}{2 \cdot 1}

b = \frac{- ( - 6 ) + 8}{2 \cdot 1} : 7

b = \frac{- ( - 6 ) - 8}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

b = 7, b = - 1

5 a^{2} - 5

2 x + 6 = x^{2} - 3 x

b^{4} (\frac{1}{3} b^{2}) (12 b^{- 8})

∣ x ∣ = 49

\frac{2 π}{\frac{2}{3}}

What are the solutions to the equation 7=b^2-6b ?
The solutions to the equation 7=b^2-6b are b=7,b=-1
Find the zeros of 7=b^2-6b
The zeros of 7=b^2-6b are b=7,b=-1