What are the solutions to the equation -8x^2-5x-16=-4x^2 ?

The solutions to the equation -8x^2-5x-16=-4x^2 are x=-5/8-i(sqrt(231))/8 ,x=-5/8+i(sqrt(231))/8

Find the zeros of -8x^2-5x-16=-4x^2

The zeros of -8x^2-5x-16=-4x^2 are x=-5/8-i(sqrt(231))/8 ,x=-5/8+i(sqrt(231))/8

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- 8 x^{2} - 5 x - 16 = - 4 x^{2}

x = - \frac{5}{8} - i \frac{231}{8}, x = - \frac{5}{8} + i \frac{231}{8}

Solution steps

- 8 x^{2} - 5 x - 16 = - 4 x^{2}

Move

4 x^{2}

to the left side

- 4 x^{2} - 5 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 ( - 4 ) ( - 16 )}{2 ( - 4 )}

Simplify

(- 5)^{2} - 4 (- 4) (- 16) : 231 i

x_{1, 2} = \frac{- ( - 5 ) \pm 231 i}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 231 i}{2 ( - 4 )}, x_{2} = \frac{- ( - 5 ) - 231 i}{2 ( - 4 )}

x = \frac{- ( - 5 ) + 231 i}{2 ( - 4 )} : - \frac{5}{8} - i \frac{231}{8}

x = \frac{- ( - 5 ) - 231 i}{2 ( - 4 )} : - \frac{5}{8} + i \frac{231}{8}

The solutions to the quadratic equation are:

x = - \frac{5}{8} - i \frac{231}{8}, x = - \frac{5}{8} + i \frac{231}{8}

0 = x^{2} + 4 x + 5

\frac{11 e ^{9}}{22 e ^{10}}

5 x^{2} - 16 x + 3

x^{2} + 18 x + 32

n - 73 \geq 438

What are the solutions to the equation -8x^2-5x-16=-4x^2 ?
The solutions to the equation -8x^2-5x-16=-4x^2 are x=-5/8-i(sqrt(231))/8 ,x=-5/8+i(sqrt(231))/8
Find the zeros of -8x^2-5x-16=-4x^2
The zeros of -8x^2-5x-16=-4x^2 are x=-5/8-i(sqrt(231))/8 ,x=-5/8+i(sqrt(231))/8