What are the solutions to the equation 4p^2-4p-15=0 ?

The solutions to the equation 4p^2-4p-15=0 are p= 5/2 ,p=-3/2

Find the zeros of 4p^2-4p-15=0

The zeros of 4p^2-4p-15=0 are p= 5/2 ,p=-3/2

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4 p^{2} - 4 p - 15 = 0

p = \frac{5}{2}, p = - \frac{3}{2}

Decimal Notation

p = 2.5, p = - 1.5

Solution steps

4 p^{2} - 4 p - 15 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 ( - 15 )}{2 \cdot 4}

(- 4)^{2} - 4 \cdot 4 (- 15) = 16

p_{1, 2} = \frac{- ( - 4 ) \pm 16}{2 \cdot 4}

Separate the solutions

p_{1} = \frac{- ( - 4 ) + 16}{2 \cdot 4}, p_{2} = \frac{- ( - 4 ) - 16}{2 \cdot 4}

p = \frac{- ( - 4 ) + 16}{2 \cdot 4} : \frac{5}{2}

p = \frac{- ( - 4 ) - 16}{2 \cdot 4} : - \frac{3}{2}

The solutions to the quadratic equation are:

p = \frac{5}{2}, p = - \frac{3}{2}

16 x^{2} - 169 y^{2}

9 t^{3} - 90 t^{2} + 144 t

(\frac{1}{3} - i \frac{2 5}{3} - \frac{1}{3})^{2}

4 a - 3 + 2 a = 7 a - 2

z^{2} + 3 z - 40

What are the solutions to the equation 4p^2-4p-15=0 ?
The solutions to the equation 4p^2-4p-15=0 are p= 5/2 ,p=-3/2
Find the zeros of 4p^2-4p-15=0
The zeros of 4p^2-4p-15=0 are p= 5/2 ,p=-3/2