What is factor z^2+3z-40 ?

The solution to factor z^2+3z-40 is (z-5)(z+8)

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factor z^2+3z-40

factor

z^{2} + 3 z - 40

(z - 5) (z + 8)

Solution steps

z^{2} + 3 z - 40

Break the expression into groups

= (z^{2} - 5 z) + (8 z - 40)

Factor out

z

from

z^{2} - 5 z : z (z - 5)

Factor out

8

from

8 z - 40 : 8 (z - 5)

= z (z - 5) + 8 (z - 5)

Factor out common term

z - 5

= (z - 5) (z + 8)

10.36 - 0.094 \cdot 0 + 0.131 \cdot 12 + 0.21 \cdot 12

1 = - \frac{3 \cdot 1 ^{4} ( - 4 \cdot 1 ^{9} + c _{1} ) ^{\frac{3}{4}}}{- 4 \cdot 1 ^{9} + c _{1}}

- x^{2} = 4 - 5 x

\frac{5}{3} - (\frac{2}{5} \cdot \frac{7}{2}) - \frac{1}{3}

6 - 4 (6 n + 7) \geq 122