What are the solutions to the equation -x^2=4-5x ?

The solutions to the equation -x^2=4-5x are x=1,x=4

Find the zeros of -x^2=4-5x

The zeros of -x^2=4-5x are x=1,x=4

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- x^{2} = 4 - 5 x

x = 1, x = 4

Solution steps

- x^{2} = 4 - 5 x

Move

5 x

to the left side

- x^{2} + 5 x = 4

Move

4

to the left side

- x^{2} + 5 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 1 ) ( - 4 )}{2 ( - 1 )}

5^{2} - 4 (- 1) (- 4) = 3

x_{1, 2} = \frac{- 5 \pm 3}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 5 + 3}{2 ( - 1 )}, x_{2} = \frac{- 5 - 3}{2 ( - 1 )}

x = \frac{- 5 + 3}{2 ( - 1 )} : 1

x = \frac{- 5 - 3}{2 ( - 1 )} : 4

The solutions to the quadratic equation are:

x = 1, x = 4

\frac{5}{3} - (\frac{2}{5} \cdot \frac{7}{2}) - \frac{1}{3}

6 - 4 (6 n + 7) \geq 122

x + 2 = x - 3

b - 4 \leq 0

x^{2} - 3 x + 2 = 0

What are the solutions to the equation -x^2=4-5x ?
The solutions to the equation -x^2=4-5x are x=1,x=4
Find the zeros of -x^2=4-5x
The zeros of -x^2=4-5x are x=1,x=4