What are the solutions to the equation x^2-3x+2=0 ?

The solutions to the equation x^2-3x+2=0 are x=2,x=1

Find the zeros of x^2-3x+2=0

The zeros of x^2-3x+2=0 are x=2,x=1

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x^{2} - 3 x + 2 = 0

x = 2, x = 1

Solution steps

x^{2} - 3 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot 2 = 1

x_{1, 2} = \frac{- ( - 3 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 1}{2 \cdot 1}

x = \frac{- ( - 3 ) + 1}{2 \cdot 1} : 2

x = \frac{- ( - 3 ) - 1}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 2, x = 1

- 25 x^{2} + 30 x + 16

∣ 1 - x ∣ = 14

8 y^{2} + 2 y - 3 = 0

\frac{x + 3}{4} > \frac{2 x - 4}{3}

6 + 9 z + z^{2} = 0

What are the solutions to the equation x^2-3x+2=0 ?
The solutions to the equation x^2-3x+2=0 are x=2,x=1
Find the zeros of x^2-3x+2=0
The zeros of x^2-3x+2=0 are x=2,x=1