What is 3x^3(2x^{2y})4^{x^2y} ?

The solution to 3x^3(2x^{2y})4^{x^2y} is 3*2^{2x^2y+1}x^{2y+3}

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simplify 3x^3(2x^{2y})4^{x^2y}

simplify

3 x^{3} (2 x^{2 y}) 4^{x^{2} y}

3 \cdot 2^{2 x^{2} y + 1} x^{2 y + 3}

Solution steps

3 x^{3} (2 x^{2 y}) \cdot 4^{x^{2} y}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

x^{3} x^{2 y} = x^{3 + 2 y}

= 3 \cdot 2 x^{3 + 2 y} \cdot 4^{x^{2} y}

Factor integer

4 = 2^{2}

= 3 \cdot 2 x^{3 + 2 y} (2^{2})^{x^{2} y}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

(2^{2})^{x^{2} y} = 2^{2 x^{2} y}

= 3 \cdot 2 x^{3 + 2 y} \cdot 2^{2 x^{2} y}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

2 \cdot 2^{2 x^{2} y} = 2^{1 + 2 x^{2} y}

= 3 x^{3 + 2 y} \cdot 2^{1 + 2 x^{2} y}

3 (3 e^{3 x} cos (2 x))

e^{- (1 + 0.5 x)^{- 2}}

\frac{( - 3 n + 6 ) ^{2}}{n ^{2}}

0.65 \cdot 1 0^{- 1}

- e^{- l n (9)}

What is 3x^3(2x^{2y})4^{x^2y} ?
The solution to 3x^3(2x^{2y})4^{x^2y} is 3*2^{2x^2y+1}x^{2y+3}