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Popular >

simplify evaluate(-2/3)^2

Solution

simplify

e v a l u a t e (- \frac{2}{3})^{2}

Solution

\frac{4 e ^{2} l v a ^{2} u t}{9}

Solution steps

e v a l u a t e (- \frac{2}{3})^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

ee = e^{1 + 1}

= v a l u a t e^{1 + 1} (- \frac{2}{3})^{2}

Add the numbers:

1 + 1 = 2

= v a l u a t e^{2} (- \frac{2}{3})^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

aa = a^{1 + 1}

= v l u a^{1 + 1} t e^{2} (- \frac{2}{3})^{2}

Add the numbers:

1 + 1 = 2

= v l u a^{2} t e^{2} (- \frac{2}{3})^{2}

(- \frac{2}{3})^{2} = \frac{2 ^{2}}{3 ^{2}}

= e^{2} \frac{2 ^{2}}{3 ^{2}} l v a^{2} u t

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 ^{2} v l u a ^{2} t e ^{2}}{3 ^{2}}

Refine

= \frac{4 e ^{2} l v a ^{2} u t}{9}

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Frequently Asked Questions (FAQ)

What is evaluate(-2/3)^2 ?
The solution to evaluate(-2/3)^2 is (4e^2lva^2ut)/9