What is l((sin(t)-cos(t))e^{-2t}) ?

The solution to l((sin(t)-cos(t))e^{-2t}) is (l(sin(t)-cos(t)))/(e^{2t)}

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simplify l((sin(t)-cos(t))e^{-2t})

simplify

l ((sin (t) - cos (t)) e^{- 2 t})

\frac{l ( sin ( t ) - cos ( t ) )}{e ^{2 t}}

Solution steps

l ((sin (t) - cos (t)) e^{- 2 t})

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= l \frac{1}{e ^{2 t}} (sin (t) - cos (t))

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot l ( sin ( t ) - cos ( t ) )}{e ^{2 t}}

Multiply:

1 \cdot l = l

= \frac{l ( sin ( t ) - cos ( t ) )}{e ^{2 t}}

0.5 x (x y)^{- 0.5}

e^{- 2 x^{7}} x^{- 8}

(e^{\frac{h v}{k T}} - 1)^{- 1}

(\frac{2}{9}) e^{- 1}

What is l((sin(t)-cos(t))e^{-2t}) ?
The solution to l((sin(t)-cos(t))e^{-2t}) is (l(sin(t)-cos(t)))/(e^{2t)}