What is (4+2i)/(6-i) ?

The solution to (4+2i)/(6-i) is 22/37+16/37 i

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simplify (4+2i)/(6-i)

simplify

\frac{4 + 2 i}{6 - i}

\frac{22}{37} + \frac{16}{37} i

Solution steps

\frac{4 + 2 i}{6 - i}

Multiply by the conjugate

\frac{6 + i}{6 + i}

= \frac{( 4 + 2 i ) ( 6 + i )}{( 6 - i ) ( 6 + i )}

Simplify

\frac{( 4 + 2 i ) ( 6 + i )}{( 6 - i ) ( 6 + i )} : \frac{22 + 16 i}{37}

= \frac{22 + 16 i}{37}

Rewrite in standard complex form:

\frac{22}{37} + \frac{16}{37} i

= \frac{22}{37} + \frac{16}{37} i

x^{2} - 4 x + 2 > 0

\frac{2}{( 1 + 1 ) ^{3}}

3 y^{2} - 48

x^{4} - 9 x^{3} + 12 x^{2} + 80 x - 192

(\frac{1}{x ^{2} - 3 x - 54})^{\frac{1}{2}}