What is (1/(x^2-3x-54))^{1/2} ?

The solution to (1/(x^2-3x-54))^{1/2} is 1/((x^2-3x-54)^{1/2)}

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simplify (1/(x^2-3x-54))^{1/2}

simplify

(\frac{1}{x ^{2} - 3 x - 54})^{\frac{1}{2}}

\frac{1}{( x ^{2} - 3 x - 54 ) ^{\frac{1}{2}}}

Solution steps

(\frac{1}{x ^{2} - 3 x - 54})^{\frac{1}{2}}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{1 ^{\frac{1}{2}}}{( x ^{2} - 3 x - 54 ) ^{\frac{1}{2}}}

Apply rule

1^{a} = 1

1^{\frac{1}{2}} = 1

= \frac{1}{( x ^{2} - 3 x - 54 ) ^{\frac{1}{2}}}

3 x + 2 (2 x + 1) = 4 (3 + x)

10 \cdot 1 0^{- 3}

16 x^{3} + 128

3 (x - 10)^{2} = 48

- \frac{3}{4} + \frac{7}{8} - \frac{1}{10}

What is (1/(x^2-3x-54))^{1/2} ?
The solution to (1/(x^2-3x-54))^{1/2} is 1/((x^2-3x-54)^{1/2)}