What are the solutions to the equation -x^2+9x=0 ?

The solutions to the equation -x^2+9x=0 are x=0,x=9

Find the zeros of -x^2+9x=0

The zeros of -x^2+9x=0 are x=0,x=9

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- x^{2} + 9 x = 0

x = 0, x = 9

Solution steps

- x^{2} + 9 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

9^{2} - 4 (- 1) \cdot 0 = 9

x_{1, 2} = \frac{- 9 \pm 9}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 9 + 9}{2 ( - 1 )}, x_{2} = \frac{- 9 - 9}{2 ( - 1 )}

x = \frac{- 9 + 9}{2 ( - 1 )} : 0

x = \frac{- 9 - 9}{2 ( - 1 )} : 9

The solutions to the quadratic equation are:

x = 0, x = 9

n + 4 n - 22 = 7 n

\frac{6 i}{3 - i}

- 4 x^{2} - 8 x + 192 = 0

2 x^{4} + 18 x^{2}

3 ∣ x - 5 ∣ + 6 = 9

What are the solutions to the equation -x^2+9x=0 ?
The solutions to the equation -x^2+9x=0 are x=0,x=9
Find the zeros of -x^2+9x=0
The zeros of -x^2+9x=0 are x=0,x=9