What are the solutions to the equation x^2+6x-4=36 ?

The solutions to the equation x^2+6x-4=36 are x=4,x=-10

Find the zeros of x^2+6x-4=36

The zeros of x^2+6x-4=36 are x=4,x=-10

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x^{2} + 6 x - 4 = 36

x = 4, x = - 10

Solution steps

x^{2} + 6 x - 4 = 36

Move

36

to the left side

x^{2} + 6 x - 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 40 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 40) = 14

x_{1, 2} = \frac{- 6 \pm 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 14}{2 \cdot 1}, x_{2} = \frac{- 6 - 14}{2 \cdot 1}

x = \frac{- 6 + 14}{2 \cdot 1} : 4

x = \frac{- 6 - 14}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = 4, x = - 10

\frac{x + 3}{x - 5} < 0

3 t^{2} - 24 t + 45

128 x^{4} - 8 y^{4}

4 x - x^{2} = x

455

What are the solutions to the equation x^2+6x-4=36 ?
The solutions to the equation x^2+6x-4=36 are x=4,x=-10
Find the zeros of x^2+6x-4=36
The zeros of x^2+6x-4=36 are x=4,x=-10