What are the solutions to the equation 4x^2+5x-21=0 ?

The solutions to the equation 4x^2+5x-21=0 are x= 7/4 ,x=-3

Find the zeros of 4x^2+5x-21=0

The zeros of 4x^2+5x-21=0 are x= 7/4 ,x=-3

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4 x^{2} + 5 x - 21 = 0

x = \frac{7}{4}, x = - 3

Solution steps

4 x^{2} + 5 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 4 ( - 21 )}{2 \cdot 4}

5^{2} - 4 \cdot 4 (- 21) = 19

x_{1, 2} = \frac{- 5 \pm 19}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 5 + 19}{2 \cdot 4}, x_{2} = \frac{- 5 - 19}{2 \cdot 4}

x = \frac{- 5 + 19}{2 \cdot 4} : \frac{7}{4}

x = \frac{- 5 - 19}{2 \cdot 4} : - 3

The solutions to the quadratic equation are:

x = \frac{7}{4}, x = - 3

n^{2} = - 18 - 9 n

3 x^{2} + 21 x - 24

\frac{2}{5} - \frac{1}{3}

3 s^{3} - 6 s

\frac{4.01}{4.01 - 4}

What are the solutions to the equation 4x^2+5x-21=0 ?
The solutions to the equation 4x^2+5x-21=0 are x= 7/4 ,x=-3
Find the zeros of 4x^2+5x-21=0
The zeros of 4x^2+5x-21=0 are x= 7/4 ,x=-3