What are the solutions to the equation x^2+0.5x-14=0 ?

The solutions to the equation x^2+0.5x-14=0 are x= 7/2 ,x=-4

Find the zeros of x^2+0.5x-14=0

The zeros of x^2+0.5x-14=0 are x= 7/2 ,x=-4

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x^{2} + 0.5 x - 14 = 0

x = \frac{7}{2}, x = - 4

Solution steps

x^{2} + 0.5 x - 14 = 0

Multiply both sides by

10

10 x^{2} + 5 x - 140 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 10 ( - 140 )}{2 \cdot 10}

5^{2} - 4 \cdot 10 (- 140) = 75

x_{1, 2} = \frac{- 5 \pm 75}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 5 + 75}{2 \cdot 10}, x_{2} = \frac{- 5 - 75}{2 \cdot 10}

x = \frac{- 5 + 75}{2 \cdot 10} : \frac{7}{2}

x = \frac{- 5 - 75}{2 \cdot 10} : - 4

The solutions to the quadratic equation are:

x = \frac{7}{2}, x = - 4

- 4 x^{2} + 6 x + 2 = 0

\frac{25 x ^{3} y}{125 x ^{3} y ^{2}}

7^{2} + 2 4^{2}

- x^{2} + x - 7 = 0

- 2.4 (3) + 9.6

What are the solutions to the equation x^2+0.5x-14=0 ?
The solutions to the equation x^2+0.5x-14=0 are x= 7/2 ,x=-4
Find the zeros of x^2+0.5x-14=0
The zeros of x^2+0.5x-14=0 are x= 7/2 ,x=-4