What is (3x^3y)(2xz^2)(4y^2z) ?

The solution to (3x^3y)(2xz^2)(4y^2z) is 24x^4y^3z^3

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simplify (3x^3y)(2xz^2)(4y^2z)

simplify

(3 x^{3} y) (2 x z^{2}) (4 y^{2} z)

24 x^{4} y^{3} z^{3}

Solution steps

(3 x^{3} y) (2 x z^{2}) (4 y^{2} z)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

x^{3} x = x^{3 + 1}

= 3 y \cdot 2 x^{3 + 1} z^{2} \cdot 4 y^{2} z

Add the numbers:

3 + 1 = 4

= 3 y \cdot 2 x^{4} z^{2} \cdot 4 y^{2} z

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

y y^{2} = y^{1 + 2}

= 3 \cdot 2 x^{4} z^{2} \cdot 4 y^{1 + 2} z

Add the numbers:

1 + 2 = 3

= 3 \cdot 2 x^{4} z^{2} \cdot 4 y^{3} z

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

z^{2} z = z^{2 + 1}

= 3 \cdot 2 x^{4} \cdot 4 y^{3} z^{2 + 1}

Add the numbers:

2 + 1 = 3

= 3 \cdot 2 x^{4} \cdot 4 y^{3} z^{3}

Multiply the numbers:

3 \cdot 2 \cdot 4 = 24

= 24 x^{4} y^{3} z^{3}

(4 h^{4}) (6 h^{2} j^{3})

(- 3 e^{3 x}) (x e^{- x})

6.39 \cdot 1 0^{- 5}

(c e^{x}) (c e^{x})

e^{- 0.3 x} (cos (x) + sin (x))

What is (3x^3y)(2xz^2)(4y^2z) ?
The solution to (3x^3y)(2xz^2)(4y^2z) is 24x^4y^3z^3