What is the d/(dt)((x)(16te^{(-t)})) ?

The d/(dt)((x)(16te^{(-t)})) is 16x(e^{-t}-e^{-t}t)

What is the first d/(dt)((x)(16te^{(-t)})) ?

The first d/(dt)((x)(16te^{(-t)})) is 16x(e^{-t}-e^{-t}t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d t} ((x) (16 t e^{(- t)}))

16 x (e^{- t} - e^{- t} t)

Solution steps

\frac{d}{d t} ((x) (16 t e^{(- t)}))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x \cdot 16 \frac{d}{d t} (t e^{- t})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = t, g = e^{- t}

= x \cdot 16 (\frac{d t}{d t} e^{- t} + \frac{d}{d t} (e^{- t}) t)

\frac{d t}{d t} = 1

\frac{d}{d t} (e^{- t}) = - e^{- t}

= x \cdot 16 (1 \cdot e^{- t} + (- e^{- t}) t)

Simplify

= 16 x (e^{- t} - e^{- t} t)

e^{- 0.8 x}

e^{4} (H (t - 3) \cdot e^{- 1})

25511428.57 \cdot 1 0^{- 9}

4.98 \cdot 1 0^{- 10} \cdot 2

What is the d/(dt)((x)(16te^{(-t)})) ?
The d/(dt)((x)(16te^{(-t)})) is 16x(e^{-t}-e^{-t}t)
What is the first d/(dt)((x)(16te^{(-t)})) ?
The first d/(dt)((x)(16te^{(-t)})) is 16x(e^{-t}-e^{-t}t)