What are the solutions to the equation 5^2+12^2=c^2 ?

The solutions to the equation 5^2+12^2=c^2 are c=13,c=-13

Find the zeros of 5^2+12^2=c^2

The zeros of 5^2+12^2=c^2 are c=13,c=-13

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5^{2} + 1 2^{2} = c^{2}

c = 13, c = - 13

Solution steps

5^{2} + 1 2^{2} = c^{2}

Switch sides

c^{2} = 5^{2} + 1 2^{2}

Simplify

5^{2} + 1 2^{2} : 169

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 169, c = - 169

169 = 13

- 169 = - 13

c = 13, c = - 13

x^{2} = 4 x + 3

\frac{5 j ^{4}}{( 2 j ^{4} ) ^{4}}

144 = - 12 (x + 5)

2 ∣ x - 2 ∣ > 8

2 x^{2} - 15 x = 8

What are the solutions to the equation 5^2+12^2=c^2 ?
The solutions to the equation 5^2+12^2=c^2 are c=13,c=-13
Find the zeros of 5^2+12^2=c^2
The zeros of 5^2+12^2=c^2 are c=13,c=-13