What are the solutions to the equation 2x^2-15x=8 ?

The solutions to the equation 2x^2-15x=8 are x=8,x=-1/2

Find the zeros of 2x^2-15x=8

The zeros of 2x^2-15x=8 are x=8,x=-1/2

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2 x^{2} - 15 x = 8

x = 8, x = - \frac{1}{2}

Solution steps

2 x^{2} - 15 x = 8

Move

8

to the left side

2 x^{2} - 15 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 2 ( - 8 )}{2 \cdot 2}

(- 15)^{2} - 4 \cdot 2 (- 8) = 17

x_{1, 2} = \frac{- ( - 15 ) \pm 17}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 17}{2 \cdot 2}, x_{2} = \frac{- ( - 15 ) - 17}{2 \cdot 2}

x = \frac{- ( - 15 ) + 17}{2 \cdot 2} : 8

x = \frac{- ( - 15 ) - 17}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = 8, x = - \frac{1}{2}

x^{3} + 6 x^{2} + 25 x + 150

x^{2} - 6 x + 7 = 0

x^{6} x^{9}

lo g_{2} (3) \cdot lo g_{3} (4)

What are the solutions to the equation 2x^2-15x=8 ?
The solutions to the equation 2x^2-15x=8 are x=8,x=-1/2
Find the zeros of 2x^2-15x=8
The zeros of 2x^2-15x=8 are x=8,x=-1/2