What is 293*(1.38*10^{-23}) ?

The solution to 293*(1.38*10^{-23}) is (20217)/(10^{23)*50}

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simplify 293(1.3810^{-23})

simplify

293 \cdot (1.38 \cdot 1 0^{- 23})

\frac{20217}{1 0 ^{23} \cdot 50}

Decimal Notation

4.0434 E - 21

Solution steps

293 (1.38 \cdot 1 0^{- 23})

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 23} = \frac{1}{1 0 ^{23}}

= 293 \cdot 1.38 \cdot \frac{1}{1 0 ^{23}}

1.38 \cdot \frac{1}{1 0 ^{23}} = \frac{69}{50 \cdot 1 0 ^{23}}

= 293 \cdot \frac{69}{50 \cdot 1 0 ^{23}}

293 \cdot \frac{69}{50 \cdot 1 0 ^{23}} = \frac{20217}{1 0 ^{23} \cdot 50}

= \frac{20217}{1 0 ^{23} \cdot 50}

2 \cdot 3^{^{'}}

- 2.5 \cdot 1 0^{- 10} (460)

\frac{( - 1 ) ^{n}}{( ln ( n ) ) ^{n}}

e^{- 100000000}

What is 293*(1.38*10^{-23}) ?
The solution to 293*(1.38*10^{-23}) is (20217)/(10^{23)*50}