What are the solutions to the equation 9x^2+8x-1=0 ?

The solutions to the equation 9x^2+8x-1=0 are x= 1/9 ,x=-1

Find the zeros of 9x^2+8x-1=0

The zeros of 9x^2+8x-1=0 are x= 1/9 ,x=-1

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9 x^{2} + 8 x - 1 = 0

x = \frac{1}{9}, x = - 1

Decimal Notation

x = 0.11111 \dots, x = - 1

Solution steps

9 x^{2} + 8 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 9 ( - 1 )}{2 \cdot 9}

8^{2} - 4 \cdot 9 (- 1) = 10

x_{1, 2} = \frac{- 8 \pm 10}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 8 + 10}{2 \cdot 9}, x_{2} = \frac{- 8 - 10}{2 \cdot 9}

x = \frac{- 8 + 10}{2 \cdot 9} : \frac{1}{9}

x = \frac{- 8 - 10}{2 \cdot 9} : - 1

The solutions to the quadratic equation are:

x = \frac{1}{9}, x = - 1

(- 2 + 3 i)^{2}

\frac{x ^{2} - y ^{2}}{x - y}

\frac{( 7 ^{16} + 7 ^{14} )}{50}

43 (x + 3) = 78 (3 x + 28) - 5

x^{3} - 5 x^{2} - x + 5 \geq 0

What are the solutions to the equation 9x^2+8x-1=0 ?
The solutions to the equation 9x^2+8x-1=0 are x= 1/9 ,x=-1
Find the zeros of 9x^2+8x-1=0
The zeros of 9x^2+8x-1=0 are x= 1/9 ,x=-1