What are the solutions to the equation x^2+10x+25=81 ?

The solutions to the equation x^2+10x+25=81 are x=4,x=-14

Find the zeros of x^2+10x+25=81

The zeros of x^2+10x+25=81 are x=4,x=-14

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x^{2} + 10 x + 25 = 81

x = 4, x = - 14

Solution steps

x^{2} + 10 x + 25 = 81

Move

81

to the left side

x^{2} + 10 x - 56 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot ( - 56 )}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot (- 56) = 18

x_{1, 2} = \frac{- 10 \pm 18}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 18}{2 \cdot 1}, x_{2} = \frac{- 10 - 18}{2 \cdot 1}

x = \frac{- 10 + 18}{2 \cdot 1} : 4

x = \frac{- 10 - 18}{2 \cdot 1} : - 14

The solutions to the quadratic equation are:

x = 4, x = - 14

2 y^{\frac{1}{2}} \cdot y

- 2 x^{2} + x + 6 = 0

3 - 2 x - x^{2}

4 (3 h - 11) < 6 (2 h - 3) + 19

x^{2} + 2 x + (6 - 3) 2 = 0

What are the solutions to the equation x^2+10x+25=81 ?
The solutions to the equation x^2+10x+25=81 are x=4,x=-14
Find the zeros of x^2+10x+25=81
The zeros of x^2+10x+25=81 are x=4,x=-14