What is AU(A,B)(BU(A,B)A^') ?

The solution to AU(A,B)(BU(A,B)A^') is BA^{'+1}U(,AB)^2

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simplify AU(A,B)(BU(A,B)A^')

simplify

A U (A, B) (B U (A, B) A^{^{'}})

B A^{' + 1} U (, A B)^{2}

Solution steps

A U (A, B) (B U (A, B) A^{^{'}})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

U (A, B) U (A, B) = U (A, B)^{1 + 1}

= A B U (A, B)^{1 + 1} A^{^{^{'}}}

Add the numbers:

1 + 1 = 2

= A B U (A, B)^{2} A^{^{^{'}}}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

A A^{^{'}} = A^{1 +^{'}}

= B U (A, B)^{2} A^{1 +^{^{'}}}

13.2^{13.2}

e^{- x^{2}} (x^{2} e^{2 x})

80000 \cdot e^{- 0.12 (2)}

(\frac{1}{2})^{n} e^{- n}

1021 (1.6 \cdot 1 0^{- 19})

What is AU(A,B)(BU(A,B)A^') ?
The solution to AU(A,B)(BU(A,B)A^') is BA^{'+1}U(,AB)^2