What is (-3x^2y^{-5})^{-3^'} ?

The solution to (-3x^2y^{-5})^{-3^'} is 1/((-\frac{3x^2){y^5})^{3^'}}

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simplify (-3x^2y^{-5})^{-3^'}

simplify

(- 3 x^{2} y^{- 5})^{- 3^{^{'}}}

\frac{1}{( - \frac{3 x ^{2}}{y ^{5}} ) ^{3^{'}}}

Solution steps

(- 3 x^{2} y^{- 5})^{- 3^{^{'}}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{( - 3 x ^{2} y ^{- 5} ) ^{3^{^{^{'}}}}}

(- 3 x^{2} y^{- 5})^{3^{^{'}}} = (- \frac{3 x ^{2}}{y ^{5}})^{3^{^{'}}}

= \frac{1}{( - \frac{3 x ^{2}}{y ^{5}} ) ^{3^{^{^{'}}}}}

e^{x^{2}} (2 x e^{- x^{2}})

(2 (- d + 1))^{1 - d}

3.17 \cdot 1 0^{- 6}

\frac{e ^{6}}{e ^{9}}

4.16 \cdot 1 0^{- 9} \cdot 1000

What is (-3x^2y^{-5})^{-3^'} ?
The solution to (-3x^2y^{-5})^{-3^'} is 1/((-\frac{3x^2){y^5})^{3^'}}