What is (e^{-2t})(2e^{2t}) ?

The solution to (e^{-2t})(2e^{2t}) is 2

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simplify (e^{-2t})(2e^{2t})

simplify

(e^{- 2 t}) (2 e^{2 t})

2

Solution steps

(e^{- 2 t}) (2 e^{2 t})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

e^{- 2 t} e^{2 t} = e^{- 2 t + 2 t}

= 2 e^{- 2 t + 2 t}

Add similar elements:

- 2 t + 2 t = 0

= 2 e^{0}

Apply rule

a^{0} = 1, a \neq = 0

e^{0} = 1

= 2 \cdot 1

Multiply the numbers:

2 \cdot 1 = 2

= 2

e^{- 0.6 (2)}

20 \cdot \frac{12}{5} e^{- 20 t}

(x + 1)^{- 1} (2 (x + 4)^{- 1})

(6.82 \cdot 1 0^{- 3}) 150

8.07 \cdot 1 0^{- 8}