What are the solutions to the equation (x+4)(x-3)=0 ?

The solutions to the equation (x+4)(x-3)=0 are x=-4,x=3

Find the zeros of (x+4)(x-3)=0

The zeros of (x+4)(x-3)=0 are x=-4,x=3

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(x + 4) (x - 3) = 0

x = - 4, x = 3

Solution steps

(x + 4) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 4 = 0 or x - 3 = 0

Solve

x + 4 = 0 : x = - 4

Solve

x - 3 = 0 : x = 3

The solutions to the quadratic equation are:

x = - 4, x = 3

\frac{5 x - 9}{4} = - 2

2 x (x + 11) = 11

1 0^{2} + x^{2} = 1 8^{2}

(\frac{3}{2} x + \frac{y}{11})^{2}

\frac{2}{3} \cdot (π - π)

What are the solutions to the equation (x+4)(x-3)=0 ?
The solutions to the equation (x+4)(x-3)=0 are x=-4,x=3
Find the zeros of (x+4)(x-3)=0
The zeros of (x+4)(x-3)=0 are x=-4,x=3