What are the solutions to the equation 2x(x+11)=11 ?

The solutions to the equation 2x(x+11)=11 are x=(-11+sqrt(143))/2 ,x=-(11+sqrt(143))/2

Find the zeros of 2x(x+11)=11

The zeros of 2x(x+11)=11 are x=(-11+sqrt(143))/2 ,x=-(11+sqrt(143))/2

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2 x (x + 11) = 11

x = \frac{- 11 + 143}{2}, x = - \frac{11 + 143}{2}

Decimal Notation

x = 0.47913 \dots, x = - 11.47913 \dots

Solution steps

2 x (x + 11) = 11

Expand

2 x (x + 11) : 2 x^{2} + 22 x

2 x^{2} + 22 x = 11

Move

11

to the left side

2 x^{2} + 22 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 22 \pm 2 2 ^{2} - 4 \cdot 2 ( - 11 )}{2 \cdot 2}

2 2^{2} - 4 \cdot 2 (- 11) = 2143

x_{1, 2} = \frac{- 22 \pm 2 143}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 22 + 2 143}{2 \cdot 2}, x_{2} = \frac{- 22 - 2 143}{2 \cdot 2}

x = \frac{- 22 + 2 143}{2 \cdot 2} : \frac{- 11 + 143}{2}

x = \frac{- 22 - 2 143}{2 \cdot 2} : - \frac{11 + 143}{2}

The solutions to the quadratic equation are:

x = \frac{- 11 + 143}{2}, x = - \frac{11 + 143}{2}

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(\frac{3}{2} x + \frac{y}{11})^{2}

\frac{2}{3} \cdot (π - π)

x - 7 > 2

4 x^{2} + 76 = 16 x

What are the solutions to the equation 2x(x+11)=11 ?
The solutions to the equation 2x(x+11)=11 are x=(-11+sqrt(143))/2 ,x=-(11+sqrt(143))/2
Find the zeros of 2x(x+11)=11
The zeros of 2x(x+11)=11 are x=(-11+sqrt(143))/2 ,x=-(11+sqrt(143))/2