What are the solutions to the equation 4x^2+76=16x ?

The solutions to the equation 4x^2+76=16x are x=2+sqrt(15)i,x=2-sqrt(15)i

Find the zeros of 4x^2+76=16x

The zeros of 4x^2+76=16x are x=2+sqrt(15)i,x=2-sqrt(15)i

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4 x^{2} + 76 = 16 x

x = 2 + 15 i, x = 2 - 15 i

Solution steps

4 x^{2} + 76 = 16 x

Move

16 x

to the left side

4 x^{2} + 76 - 16 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 16 x + 76 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 4 \cdot 76}{2 \cdot 4}

Simplify

(- 16)^{2} - 4 \cdot 4 \cdot 76 : 815 i

x_{1, 2} = \frac{- ( - 16 ) \pm 8 15 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 8 15 i}{2 \cdot 4}, x_{2} = \frac{- ( - 16 ) - 8 15 i}{2 \cdot 4}

x = \frac{- ( - 16 ) + 8 15 i}{2 \cdot 4} : 2 + 15 i

x = \frac{- ( - 16 ) - 8 15 i}{2 \cdot 4} : 2 - 15 i

The solutions to the quadratic equation are:

x = 2 + 15 i, x = 2 - 15 i

\frac{1}{2} + \frac{2}{3} + \frac{3}{4} + \frac{4}{5}

\frac{m x ^{2} - m y ^{2}}{2 m + 8} \cdot \frac{3 m + 12}{m y + m x}

x^{2} - 8 x \leq - 12

lo g_{2} (3)

3 x - 6 = 4 (2 - 3 x) - 8 x

What are the solutions to the equation 4x^2+76=16x ?
The solutions to the equation 4x^2+76=16x are x=2+sqrt(15)i,x=2-sqrt(15)i
Find the zeros of 4x^2+76=16x
The zeros of 4x^2+76=16x are x=2+sqrt(15)i,x=2-sqrt(15)i