What is expand 2(1-2x^2)^{-1} ?

The solution to expand 2(1-2x^2)^{-1} is 2/(-2x^2+1)

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expand 2(1-2x^2)^{-1}

expand

2 (1 - 2 x^{2})^{- 1}

\frac{2}{- 2 x ^{2} + 1}

Solution steps

2 (1 - 2 x^{2})^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= 2 \cdot \frac{1}{( - 2 x ^{2} + 1 )}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{1 - 2 x ^{2}}

Multiply the numbers:

1 \cdot 2 = 2

= \frac{2}{1 - 2 x ^{2}}

(5 x^{3} y^{5}) (6 x y)

(6.5 \cdot 1 0^{- 5}) (0.2 - x)

e^{- 0.36 (1.5)}

e^{- \frac{5}{5.77}}

1 - 2 x 4 - x^{2}

What is expand 2(1-2x^2)^{-1} ?
The solution to expand 2(1-2x^2)^{-1} is 2/(-2x^2+1)