What is (s-1)(s-4)^4(s-7)^4(s+8) ?

The solution to (s-1)(s-4)^4(s-7)^4(s+8) is (s-4)^4(s-7)^4(s-1)(s+8)

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simplify (s-1)(s-4)^4(s-7)^4(s+8)

simplify

(s - 1) (s - 4)^{4} (s - 7)^{4} (s + 8)

(s - 4)^{4} (s - 7)^{4} (s - 1) (s + 8)

Solution steps

(s - 1) (s - 4)^{4} (s - 7)^{4} (s + 8)

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

(s - 4)^{4} (s - 7)^{4} = ((s - 4) (s - 7))^{4}

= (s - 1) ((s - 4) (s - 7))^{4} (s + 8)

((s - 4) (s - 7))^{4} = (s - 4)^{4} (s - 7)^{4}

= (s - 1) (s - 4)^{4} (s - 7)^{4} (s + 8)

x^{3} (1 + x^{4})^{3}

t^{2} e^{- 3 t} cos (2 t)

- 14 π e^{- 1^{2}}

3.4 \cdot 1 0^{- 2} \cdot 4

(0.65 \cdot 1 0^{- 16}) (0.98)

What is (s-1)(s-4)^4(s-7)^4(s+8) ?
The solution to (s-1)(s-4)^4(s-7)^4(s+8) is (s-4)^4(s-7)^4(s-1)(s+8)