What is (8i)/(9-4i) ?

The solution to (8i)/(9-4i) is -32/97+72/97 i

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simplify (8i)/(9-4i)

simplify

\frac{8 i}{9 - 4 i}

- \frac{32}{97} + \frac{72}{97} i

Solution steps

\frac{8 i}{9 - 4 i}

Multiply by the conjugate

\frac{9 + 4 i}{9 + 4 i}

= \frac{8 i ( 9 + 4 i )}{( 9 - 4 i ) ( 9 + 4 i )}

Simplify

\frac{8 i ( 9 + 4 i )}{( 9 - 4 i ) ( 9 + 4 i )} : \frac{72 i - 32}{97}

= \frac{72 i - 32}{97}

Rewrite in standard complex form:

- \frac{32}{97} + \frac{72}{97} i

= - \frac{32}{97} + \frac{72}{97} i

- 2 (x + 7)^{2} = - 162

\frac{1}{5} \frac{1}{5} = \frac{5}{5}

\frac{4 - 13}{3 - 7}

4 w^{2} + 12 w + 9 = 169

5^{2} \cdot 5^{4}