What is (3m^4n^6)(2mn)(2m^2n) ?

The solution to (3m^4n^6)(2mn)(2m^2n) is 12m^7n^8

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simplify (3m^4n^6)(2mn)(2m^2n)

simplify

(3 m^{4} n^{6}) (2 mn) (2 m^{2} n)

12 m^{7} n^{8}

Solution steps

(3 m^{4} n^{6}) (2 mn) (2 m^{2} n)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

2 \cdot 2 = 2^{1 + 1}

= 3 m^{4} n^{6} mn \cdot 2^{1 + 1} m^{2} n

Add the numbers:

1 + 1 = 2

= 3 m^{4} n^{6} mn \cdot 2^{2} m^{2} n

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

m^{4} m m^{2} = m^{4 + 1 + 2}

= 3 n^{6} n \cdot 2^{2} m^{4 + 1 + 2} n

Add the numbers:

4 + 1 + 2 = 7

= 3 n^{6} n \cdot 2^{2} m^{7} n

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

n^{6} nn = n^{6 + 1 + 1}

= 3 \cdot 2^{2} m^{7} n^{6 + 1 + 1}

Add the numbers:

6 + 1 + 1 = 8

= 3 \cdot 2^{2} m^{7} n^{8}

2^{2} = 4

= 3 \cdot 4 m^{7} n^{8}

Multiply the numbers:

3 \cdot 4 = 12

= 12 m^{7} n^{8}

(- 120 e^{- 2 t}) (6 e^{- 2 t})

\frac{d}{d t} (e^{- (s + 4) t})

[(2 x + 1)^{7}]^{^{'}}

\frac{e ^{- 0.05 t}}{e ^{0.2 t}}

What is (3m^4n^6)(2mn)(2m^2n) ?
The solution to (3m^4n^6)(2mn)(2m^2n) is 12m^7n^8