What is (2-1/2)(3-2/3)+41^2 ?

The solution to (2-1/2)(3-2/3)+41^2 is 1684 1/2

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(2-1/2)(3-2/3)+41^2

(2 - \frac{1}{2}) (3 - \frac{2}{3}) + 4 1^{2}

1684 \frac{1}{2}

Solution steps

(2 - \frac{1}{2}) (3 - \frac{2}{3}) + 4 1^{2}

Follow the PEMDAS order of operations

Calculate within parentheses

(2 - \frac{1}{2}) : \frac{3}{2}

= \frac{3}{2} (3 - \frac{2}{3}) + 4 1^{2}

Calculate within parentheses

(3 - \frac{2}{3}) : \frac{7}{3}

= \frac{3}{2} \cdot \frac{7}{3} + 4 1^{2}

Calculate exponents

4 1^{2} : 1681

= \frac{3}{2} \cdot \frac{7}{3} + 1681

Multiply and divide (left to right)

\frac{3}{2} \cdot \frac{7}{3} : \frac{7}{2}

= \frac{7}{2} + 1681

Add and subtract (left to right)

\frac{7}{2} + 1681 : \frac{3369}{2}

= \frac{3369}{2}

Convert improper fractions to mixed numbers:

\frac{3369}{2} = 1684 \frac{1}{2}

= 1684 \frac{1}{2}

10 - 6 v = - 104

\frac{\frac{x}{y}}{z}

5 (x - 2)^{2} + 20 = - 60

x^{2} + x - 30 \leq 0