What are the solutions to the equation y^2-7y+10=0 ?

The solutions to the equation y^2-7y+10=0 are y=5,y=2

Find the zeros of y^2-7y+10=0

The zeros of y^2-7y+10=0 are y=5,y=2

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y^{2} - 7 y + 10 = 0

y = 5, y = 2

Solution steps

y^{2} - 7 y + 10 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 10 = 3

y_{1, 2} = \frac{- ( - 7 ) \pm 3}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 7 ) + 3}{2 \cdot 1}, y_{2} = \frac{- ( - 7 ) - 3}{2 \cdot 1}

y = \frac{- ( - 7 ) + 3}{2 \cdot 1} : 5

y = \frac{- ( - 7 ) - 3}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

y = 5, y = 2

\frac{1}{4} (16)^{- \frac{3}{4}}

\frac{3}{2} (- 2)^{3 - 1}

∣ 2 x - 1 ∣ \leq 1

x^{4} - 9 x^{2} + 8 = 0

9 x + 5 - 8 x + 14 = 20

What are the solutions to the equation y^2-7y+10=0 ?
The solutions to the equation y^2-7y+10=0 are y=5,y=2
Find the zeros of y^2-7y+10=0
The zeros of y^2-7y+10=0 are y=5,y=2