What are the solutions to the equation h^2+2h=35 ?

The solutions to the equation h^2+2h=35 are h=5,h=-7

Find the zeros of h^2+2h=35

The zeros of h^2+2h=35 are h=5,h=-7

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h^{2} + 2 h = 35

h = 5, h = - 7

Solution steps

h^{2} + 2 h = 35

Move

35

to the left side

h^{2} + 2 h - 35 = 0

Solve with the quadratic formula

h_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 35 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 35) = 12

h_{1, 2} = \frac{- 2 \pm 12}{2 \cdot 1}

Separate the solutions

h_{1} = \frac{- 2 + 12}{2 \cdot 1}, h_{2} = \frac{- 2 - 12}{2 \cdot 1}

h = \frac{- 2 + 12}{2 \cdot 1} : 5

h = \frac{- 2 - 12}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

h = 5, h = - 7

(9)^{\frac{1}{2}}

\frac{60 - 2 ( \frac{b 5}{6} )}{3} = b

(5 x^{2} y) (\frac{2}{5} x y^{5})

3 = - x^{2}

8 x - 15 = 3 x

What are the solutions to the equation h^2+2h=35 ?
The solutions to the equation h^2+2h=35 are h=5,h=-7
Find the zeros of h^2+2h=35
The zeros of h^2+2h=35 are h=5,h=-7