What are the solutions to the equation -2x^2+4x-7=0 ?

The solutions to the equation -2x^2+4x-7=0 are x=1-isqrt(5/2),x=1+isqrt(5/2)

Find the zeros of -2x^2+4x-7=0

The zeros of -2x^2+4x-7=0 are x=1-isqrt(5/2),x=1+isqrt(5/2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 2 x^{2} + 4 x - 7 = 0

x = 1 - i \frac{5}{2}, x = 1 + i \frac{5}{2}

Solution steps

- 2 x^{2} + 4 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 2 ) ( - 7 )}{2 ( - 2 )}

Simplify

4^{2} - 4 (- 2) (- 7) : 210 i

x_{1, 2} = \frac{- 4 \pm 2 10 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 4 + 2 10 i}{2 ( - 2 )}, x_{2} = \frac{- 4 - 2 10 i}{2 ( - 2 )}

x = \frac{- 4 + 2 10 i}{2 ( - 2 )} : 1 - i \frac{5}{2}

x = \frac{- 4 - 2 10 i}{2 ( - 2 )} : 1 + i \frac{5}{2}

The solutions to the quadratic equation are:

x = 1 - i \frac{5}{2}, x = 1 + i \frac{5}{2}

7 (2 x - 3) + 4 (x + 1) = 1

\frac{5 ( 3 ( 2 ) ^{2} - 2 ( 2 ) )}{( 3 ( 2 ) - 1 ) ^{2}}

i^{91}

((4^{4})^{4})^{4}

y^{2} - 6 y + 4 = 0

What are the solutions to the equation -2x^2+4x-7=0 ?
The solutions to the equation -2x^2+4x-7=0 are x=1-isqrt(5/2),x=1+isqrt(5/2)
Find the zeros of -2x^2+4x-7=0
The zeros of -2x^2+4x-7=0 are x=1-isqrt(5/2),x=1+isqrt(5/2)