What are the solutions to the equation y^2-6y+4=0 ?

The solutions to the equation y^2-6y+4=0 are y=3+sqrt(5),y=3-sqrt(5)

Find the zeros of y^2-6y+4=0

The zeros of y^2-6y+4=0 are y=3+sqrt(5),y=3-sqrt(5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{2} - 6 y + 4 = 0

y = 3 + 5, y = 3 - 5

Solution steps

y^{2} - 6 y + 4 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 4 = 25

y_{1, 2} = \frac{- ( - 6 ) \pm 2 5}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 6 ) + 2 5}{2 \cdot 1}, y_{2} = \frac{- ( - 6 ) - 2 5}{2 \cdot 1}

y = \frac{- ( - 6 ) + 2 5}{2 \cdot 1} : 3 + 5

y = \frac{- ( - 6 ) - 2 5}{2 \cdot 1} : 3 - 5

The solutions to the quadratic equation are:

y = 3 + 5, y = 3 - 5

k^{2} - 10 k + 24

x^{4} + x^{3} - x^{2} + x - 2

n + 5 > 21

y^{\frac{3}{2}}

10 x^{2} + 41 x + 21

What are the solutions to the equation y^2-6y+4=0 ?
The solutions to the equation y^2-6y+4=0 are y=3+sqrt(5),y=3-sqrt(5)
Find the zeros of y^2-6y+4=0
The zeros of y^2-6y+4=0 are y=3+sqrt(5),y=3-sqrt(5)