What is factor 10x^2+41x+21 ?

The solution to factor 10x^2+41x+21 is (5x+3)(2x+7)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor 10x^2+41x+21

factor

10 x^{2} + 41 x + 21

(5 x + 3) (2 x + 7)

Solution steps

10 x^{2} + 41 x + 21

Break the expression into groups

= (10 x^{2} + 6 x) + (35 x + 21)

Factor out

2 x

from

10 x^{2} + 6 x : 2 x (5 x + 3)

Factor out

7

from

35 x + 21 : 7 (5 x + 3)

= 2 x (5 x + 3) + 7 (5 x + 3)

Factor out common term

5 x + 3

= (5 x + 3) (2 x + 7)

539

a^{2} + 4 a = 0

(\frac{4}{9})^{- \frac{3}{2}}

\frac{- 2 x ^{2} - 20 x - 50}{x ^{2} + 4} \geq 0

6 x^{2} - 9 x = - 1

What is factor 10x^2+41x+21 ?
The solution to factor 10x^2+41x+21 is (5x+3)(2x+7)