What are the solutions to the equation 6x^2-9x=-1 ?

The solutions to the equation 6x^2-9x=-1 are x=(9+sqrt(57))/(12),x=(9-sqrt(57))/(12)

Find the zeros of 6x^2-9x=-1

The zeros of 6x^2-9x=-1 are x=(9+sqrt(57))/(12),x=(9-sqrt(57))/(12)

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6 x^{2} - 9 x = - 1

x = \frac{9 + 57}{12}, x = \frac{9 - 57}{12}

Decimal Notation

x = 1.37915 \dots, x = 0.12084 \dots

Solution steps

6 x^{2} - 9 x = - 1

Move

1

to the left side

6 x^{2} - 9 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 6 \cdot 1}{2 \cdot 6}

(- 9)^{2} - 4 \cdot 6 \cdot 1 = 57

x_{1, 2} = \frac{- ( - 9 ) \pm 57}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 57}{2 \cdot 6}, x_{2} = \frac{- ( - 9 ) - 57}{2 \cdot 6}

x = \frac{- ( - 9 ) + 57}{2 \cdot 6} : \frac{9 + 57}{12}

x = \frac{- ( - 9 ) - 57}{2 \cdot 6} : \frac{9 - 57}{12}

The solutions to the quadratic equation are:

x = \frac{9 + 57}{12}, x = \frac{9 - 57}{12}

3 x^{2} - 26 x + 35 = 0

- - 36

3 (x - 2) 2 - 37 = 20

(\frac{g ^{3}}{h ^{2}})^{5}

5^{- \frac{3}{2}}

What are the solutions to the equation 6x^2-9x=-1 ?
The solutions to the equation 6x^2-9x=-1 are x=(9+sqrt(57))/(12),x=(9-sqrt(57))/(12)
Find the zeros of 6x^2-9x=-1
The zeros of 6x^2-9x=-1 are x=(9+sqrt(57))/(12),x=(9-sqrt(57))/(12)