What are the solutions to the equation 4x^2-25x+6=0 ?

The solutions to the equation 4x^2-25x+6=0 are x=6,x= 1/4

Find the zeros of 4x^2-25x+6=0

The zeros of 4x^2-25x+6=0 are x=6,x= 1/4

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4 x^{2} - 25 x + 6 = 0

x = 6, x = \frac{1}{4}

Solution steps

4 x^{2} - 25 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 25 ) \pm ( - 25 ) ^{2} - 4 \cdot 4 \cdot 6}{2 \cdot 4}

(- 25)^{2} - 4 \cdot 4 \cdot 6 = 23

x_{1, 2} = \frac{- ( - 25 ) \pm 23}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 25 ) + 23}{2 \cdot 4}, x_{2} = \frac{- ( - 25 ) - 23}{2 \cdot 4}

x = \frac{- ( - 25 ) + 23}{2 \cdot 4} : 6

x = \frac{- ( - 25 ) - 23}{2 \cdot 4} : \frac{1}{4}

The solutions to the quadratic equation are:

x = 6, x = \frac{1}{4}

x^{2} - 14 x + 85 = 0

\frac{( 2 x - 7 )}{4} \leq \frac{1}{3}

16 x y^{2} + 28 x y + 8 y

x^{2} + 12 x = - 32

25 p^{2} - 40 p + 16

What are the solutions to the equation 4x^2-25x+6=0 ?
The solutions to the equation 4x^2-25x+6=0 are x=6,x= 1/4
Find the zeros of 4x^2-25x+6=0
The zeros of 4x^2-25x+6=0 are x=6,x= 1/4